Disable Java Update Notification

Fed up with getting prompted to update Java, or if you have some web application like Banner that requires a particular version??? You can use a simple registry hack to disable notification of available updates...!!!


(1). Open the Registry Editor by going to the Start button and typing in regedt32.

(2).Navigate through to the following key: HKEY_LOCAL_MACHINE\SOFTWARE\JavaSoft\Java Update\Policy

(3).Change the value of EnableAutoUpdateCheck to 0 and the value of EnableJavaUpdate to 0.
Java should no longer prompt you for the annoying updates.



Enjoy..!!!

Is this trick useful??  Comment here..
Thank you.!!  :)

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5 PROCESSES TO CHECK ARMSTRONG AND REVERSE OF NUMBER~ Unix Program

Hi reader,
  Here our task is :

• Create 5 processes.
• Find whether a number is Armstong and Reverse the same using these processes.

A :Accept number.
C:Find whether it is armstrong.
D:Print Result.
B:Calculate Reverse of the Number.
E:Display Reverse.



Here is the complete Program.


#include<stdio.h>
#include<unistd.h>
main()
{             //initially in A
int num,f1,f2,f3,f4,p1[2],p2[2],p3[2],p4[2],arm,rev,flag=0;
pipe(p1);
pipe(p2);

f1=fork();  //A created B
if(f1>0)    //A is working ..
{
f2=fork();  //A created C
if(f2>0)     //A is working...
{
printf("Enter a number   :");
scanf("%d",&num);

close(p1[0]);
close(p2[0]);
write(p1[1],&num,sizeof(num));
write(p2[1],&num,sizeof(num));
}
if(f2==0)   //C is working..
{

pipe(p3);
f3=fork(); //C created D
if(f3>0)   //C is working..
{
close(p1[1]);
read(p1[0],&num,sizeof(num));
flag=0;
for(arm=0;num>0;num/=10)
arm+=(num%10)*(num%10)*(num%10);
if(num==arm)flag=1;
close(p3[0]);
write(p3[1],&flag,sizeof(flag));
}
else if (f3==0)  //D is working..
{
close(p3[1]);
read(p3[0], &flag, sizeof(flag));
(flag)?printf("It is Armstrong Number"):("It is Not Armstrong Number");
}
}
}
if(f1==0)   //B is working..
{
sleep(2);
pipe(p4);
f4=fork(); //B created E
if(f4>0)   //B is working..{
close(p2[1]);
read(p2[0],&num,sizeof(num));
for(rev=0;num>0;num/=10)
rev=10*rev+num%10;
close(p4[0]);
write(p4[1],&rev,sizeof(rev));
}
if(f4==0)   //E is working..
{
close(p4[1]);
read(p4[0],&rev,sizeof(rev));
printf("Reverse of Number is : %d\n",rev);
}
}
}




Output
Enter a number: 153
It is Armstrong Number
Reverse of Number is :351

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Lex program ~ Read and copy file content

This lex program will read an input file and copy the content with line number to another file.

%{
#include<stdio.h>
#include<string.h>
char line[20];
int count=0,i=0;
FILE *out;
%}
%%
['\n'] { fprintf(out,"%d %s\n",++count,line);}
(.*) {
strcpy(line,yytext);
}%%
main()
{
yyin=fopen("in.c","r");
out=fopen("out.c","w");
yylex();
getch();
}
int yywrap()
{
return 1;
}







input
main()
{
int i=9, j=900,k=115;
printf("%d,i+j+k);
}


output file


1 main()
2 {
3 int i=9, j=900,k=115;
4 printf("%d,i+j+k);
5 }
6 }

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Read a file and copy content to other file~ C code

This C program will read an input file and copy the content to another file with Line numbers..!!


#include<stdio.h>
main()
{
      FILE *f1,*f2;
      int t=0;
      char line[20];
      f1=fopen("in.c","r");
      f2=fopen("out.c","w");
   
      while(!feof(f1)){
      fgets(line,20,f1);
      t++;
      fprintf(f2,"%d  %s",t,line);
      }
     getch();
      }

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Lex- Collect Tokens and sort

Hello friend,
  Here I am with an interesting Lex program which sorts all the nubers from input file and sort them. If you are well-familiarised with lex paradigm, it is very easy task.

Things to remember:

• The definition [0-9]+ can detect all the numbers from input
• The number detected at present will be pointed by yytext and have length yyleng
• Whenever a new token (here a number) is detected, yytext will be replaced with new value. 

Logic

1. Read the input
2. If a number is detected, store it in an array (we can use yytext and yyleng for this). Read each digit --> multiply with 10 --> add next digit -->continue upto last digit.

  for eg, to read 123
initialise num=0;

• read 1--> num=num*10+1-->num=0+1-->num=1
• read 2--> num=num*10+2-->num=10+2-->num=12
• read 3--> num=num*10+3-->num=120+3-->num=123

store num in an array.
3. After reading all the numbers, sort the number within the array




%{
#include<stdio.h>
int t, a[20],i,j,n,num;
%}
%%
[0-9]+ {num=0;
 for(i=0;i<yyleng;i++)
num=num*10+(yytext[i]-'0');
a[n++]=num;
}
. ;
%%
main()
{
yyin=fopen("file.c","r");
yylex();
for(i=0;i<n;i++)
for(j=0;j<n-i-1;j++)
if(a[j]>a[j+1])
{
t=a[j];
a[j]=a[j+1];
a[j+1]=t;
}
for(i=0;i<n;i++)
printf("%d\n",a[i]);

}
int yywrap()
{
return 1;
}




sample input (in file.c)
main()
{
int i=9, j=900,k=115;
printf("%d,i+j+k);
}



output
9
115
900

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Quadruple ~ C code

#include<stdio.h>
#include<string.h>

main()
{

 char line[20];
int s[20];
int t=1;
     
int i=0;     
printf("Enter string..  :");
gets(line);
for(i=0;i<20;i++)s[i]=0;
printf("op\ta1\ta2\tres\n");
for(i=2;line[i]!='\0';i++)
{
if(line[i]=='/' || line[i]=='*')
{
                printf("\n");
if(s[i]==0)
{
if(s[i+1]==0)
{
printf(":=\t%c\t\t t%d\n",line[i+1],t);
s[i+1]=t++;
}
printf("%c\t",line[i]);
(s[i-1]==0)?printf("%c\t",line[i-1]):printf("t%d\t",s[i-1]);
printf("t%d \t t%d",s[i+1],t);
s[i-1]=s[i+1]=t++;
s[i]=1;
}
}
}

for(i=2;line[i]!='\0';i++)
{
if(line[i]=='+' || line[i]=='-')
{
                printf("\n");
if(s[i]==0)
{
if(s[i+1]==0)
{
printf(":=\t%c\t\t t%d\n",line[i+1],t);
s[i+1]=t++;
}
printf("%c\t",line[i]);
(s[i-1]==0)?printf("%c\t",line[i-1]):printf("t%d\t",s[i-1]);
printf("t%d \t t%d",s[i+1],t);
s[i-1]=s[i+1]=t++;
s[i]=1;
}
}
}
printf("\n:=\tt%d\t\t%c",t-1,line[0]);



getch();
}




Output




Enter string..  :a=b*c-b*c


op      a1      a2      res
:=      c                t1
*       b       t1       t2
:=      c                t3
*       b       t3       t4
-       t2      t4       t5
:=      t5              a

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Lex and Yacc in Windows 7 - Compile and Run

Hi Friend,
I was in search for a long time to get a platform in windows-7 to run lex and Yacc ,for academic purposes. Many of my friends also had the same problem and often forced to choose Linux only for merely executing Lex & Yacc programs..!!!

At last, I found one solution and its my pleasure to share it with all of you.!!  :)

Its very simple.You need to download two very small files.
You have to download two executable( i.e.,   .exe files). In total,its size may have about 370KB.

To download them click the links below.

Link 1:   Flex

Link 2:  Bison

Save both files in same place. ( I did in D: --> Flex)
Keep the lex program to be compiled also in same place.

Now open command prompt--> reach your directory through command prompt.

To compile, type command 
                flex <filename> (eg:- flex myflex.l)

If your program is error-free, lex.yy.c will be generated.

We can compile this C file with any C compiler available (eg: Turbo C)

and generate yy.lex.exe

Now just run yy.lex.exe. Its your lexical analyser..!!!

I hope this post was useful for you.!!
Please comment your feedback here.!!
Thank You.!!  :)

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