C program to find Size of a structure without using sizeof() operator

Write a program to find the size of following structure without using size of operator

struct ABC
 {
 int a;
 float b;
 char c;
 };



Hai Viewer, confused?? Hmm.. calculating the size of a datatype without using sizeof() operator seems to be weird. But pointers will help you to solve this problem.  First u have to initialize a null pointer on intended datatype .You know that in 'structure ' separate memory will be allocated to each element. So, on incrementing that pointer variable, the value of that pointer will be incremented by size of that structure . That is our Goal..!!!! :)
Since we have initialized pointer with 0 we simply need to print the current pointer value..!!



solution

#include<stdio.h>
struct  ABC
{
    int a;
    float b;
    char c;
};
int main()
{
    struct ABC *ptr=(struct ABC *)0;
    ptr++;
printf("%d",ptr);
getch();
return 1;
}


I hope this code was useful for u!!
Have a better program for ths prblm??
Feel free to comment it here..!!  :):):)